University of St Andrews
School of Physics and Astronomy
10. Two-beam interference: Young's slits,
intensity variation by algebra
Return to the First Year Waves and Optics Home
Page
Associated tutorial questions (St Andrews only)

We are now looking at optics again, in areas where the wave-like nature of light is
important. We will look at how two beams interfere, then how many beams interfere,
and then (briefly) how an infinite number of infinitesimally small beams interfere.
We use the principle of linear superposition, as discussed earlier (ie we add up the
disturbances at one place and time due to all the present waves, and the algebraic sum is
the total disturbance there. Looking at this in optics is trickier, as we can never
measure the time-varying disturbance directly, only the time averaged
"intensity" of light at a point. The intensity of a wave is proportional
to the time average of the square of the disturbance.
- Two-beam interference is the easiest to describe, and we will take as our main example
the arrangement known as "Young's Slits"
- Our model supposes that light coming from the two slits is coherent and in phase.
- Where two waves come together in phase (in step) we get constructive interference, and a
maximum in intensity.
- Where two waves come together out of phase (ie have a phase difference of pi radians) we
get destructive interference, and a minimum in intensity.
- The above are the extremes of what may happen. In between the results is ... in
between!
- The intensity of a wave is proportional to the time average of the square of its
disturbance.
- For places where there is a phase difference other than aero or a multiple of p, we need to add up the disturbances of the two waves to find the
time-varying total disturbance. Taking the time average of this quantity then gives
us the intensity.
- We can do this to show that the intensity in the two beam interference pattern caused by
two beams each of intensity I, and with a relative phase difference between them
of f, is 4 I 2 cos2
(f / 2)
- In the Young's slits arrangement the phase difference comes from the difference in path
length that the two beams travel from the slits to the distant screen. If we are
looking at a part of the screen at an angle Q from the
straight through position, the path length difference is d sin(Q), and for each wavelength path difference there will be a 2p phase shift. Thus the phase difference between the two beams
is f = 2p d sin(Q) / l
Similar material to that presented in the lectures is available at:-
- Halliday, Resnick, & Walker - Chapters on:- Interference
Associated tutorial questions (St Andrews only)
Return to Waves and Optics Home Page
Created by, and copyright of, Bruce Sinclair, University of St
Andrews; last modified 18/09/01